(2x+3)(3x^2-4x-5)=

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Solution for (2x+3)(3x^2-4x-5)= equation: 


Simplifying
(2x + 3)(3x2 + -4x + -5) = 0

Reorder the terms:
(3 + 2x)(3x2 + -4x + -5) = 0

Reorder the terms:
(3 + 2x)(-5 + -4x + 3x2) = 0

Multiply (3 + 2x) * (-5 + -4x + 3x2)
(3(-5 + -4x + 3x2) + 2x * (-5 + -4x + 3x2)) = 0
((-5 * 3 + -4x * 3 + 3x2 * 3) + 2x * (-5 + -4x + 3x2)) = 0
((-15 + -12x + 9x2) + 2x * (-5 + -4x + 3x2)) = 0
(-15 + -12x + 9x2 + (-5 * 2x + -4x * 2x + 3x2 * 2x)) = 0
(-15 + -12x + 9x2 + (-10x + -8x2 + 6x3)) = 0

Reorder the terms:
(-15 + -12x + -10x + 9x2 + -8x2 + 6x3) = 0

Combine like terms: -12x + -10x = -22x
(-15 + -22x + 9x2 + -8x2 + 6x3) = 0

Combine like terms: 9x2 + -8x2 = 1x2
(-15 + -22x + 1x2 + 6x3) = 0

Solving
-15 + -22x + 1x2 + 6x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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